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MATHMAA

# Linear Equation Two Variable5

Linear Equation Two Variable5 consists of answers for level 3.

LEVEL - 3

1. Solve the equation using the method of substitution.

3x - 5y = -1
x - y = -1

Solution:-

3x -5y = -1           -----------(1)

x - y = -1
x = y - 1               -----------(2)

Plug (2) in (1) , We get,

3(y - 1) - 5y = -1
3y - 5y - 3 = -1
-2y = 3-1
-2y = 2
y = -1

Plug the 'y' value in (2), We get,

x = -1 - 1
x = -2

Therefore x = -2 and y = -1 .

2. Solve the equations:

$$\frac{1}{2x} - \frac{1}{y} = -1$$
$$\frac{1}{x} + \frac{1}{2y} = 8$$

Solution:-

$$\frac{1}{2x} - \frac{1}{y} = -1$$       ---------(1)
$$\frac{1}{x} + \frac{1}{2y} = 8$$       ---------(2)

(2)*$$\frac{1}{2}$$ , We get,

$$\frac{1}{2x} + \frac{1}{4y} = 4$$     ---------(3)

(3) + (2), We get,

$$\frac{1}{2x} + \frac{1}{4y} = 4$$

$$\frac{1}{2x} - \frac{1}{y} = -1$$
(-)