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e) \(2m^{2}+10\) = 210

Solution :-

\(2m^{2}+10\) = 210

Subtracting 10 on both sides we get,

\(2m^{2}\) = 200

Dividing 2 on both sides we get ,

\(m^{2}\) = 100

m = \(\pm \sqrt{100}\)

m = \(\pm \sqrt{10*10}\)                            \((\because 100 = 10*10)\)

m = \(\pm \) 10


f) \(4r^{2}+1\) = 325

Solution:-

\(4r^{2}+1\) = 325

Subtracting 1 on both sides we get,

\(4r^{2}\) = 324

Dividing 4 on both sides we get ,

\(r^{2}\) = 81

r = \(\pm \sqrt{81}\)

r = \(\pm \sqrt{9*9}\)                                 \((\because 81 = 9*9)\)

r = \(\pm 9\)


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