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c) \(x^{2} \) + 8 = 28

Solution:-

\(x^{2} \) + 8 = 28

Subtracting 8 on both sides we get,

\(x^{2} \) = 20

x = \(\pm \sqrt{20}\)

x = \(\pm \sqrt{2*2*5}\)                                \((\because 20 = 2*2*5)\)

x = \(\pm 2\sqrt{5}\)


d) \(-5x^{2}\) = -500

Solution :-

\(-5x^{2}\) = -500

Dividing -5 on both sides we get,

\(x^{2}\) = 100

x = \(\pm \sqrt{100}\)

x = \(\pm \sqrt{10*10}\)                                \((\because 100 = 10*10)\)

x = \(\pm 10\)

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