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#Q :  Referring to the function f(x) = -3sin(4x) + 2, the period of f(x) is __ π, the amplitude of f(x) is _____, and the range of f(x) is _____ (give your answer interval notation).



Solution: 

                                           f(x)           = asin(kx)+b then period is 2pi/k ,
                                      

                                        Amplitude  = |a|


                                       Range          =  [-a+b, a+b]
                                      

 
                                      f(x)             = - 3 sin(4x)+2   


                                      so period is 2pi/4=(1/2)*pi
                                     


                                      Amplitude    = 3
                                     


                                      Range            = [-3+2, 3+2] =  [-1, 5]


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